Administrator Mopar1973Man Posted October 3, 2013 Administrator Share Posted October 3, 2013 Here is a awesome article on rotational mass and its effects. http://hpwizard.com/rotational-inertia.html Just give me the answers Shaving a pound from your tires is equivalent to shaving at most 2 pounds of non-rotating weight. That's PER TIRE, so a pound off each tire could worth close to 8 pounds of weight reduction. For wheels, the multiplier is closer to 1.6, so saving 5 pounds per wheel (20 total) would feel like a static weight reduction of 32 pounds. For brake discs, it can be as low as 1.2. Regardless of the equivalent weight ratio, you're best off reducing weight as much as possible, as you might expect. Link to comment Share on other sites More sharing options...
dorkweed Posted October 3, 2013 Share Posted October 3, 2013 Way over my head!!! But thanks!! Link to comment Share on other sites More sharing options...
Administrator Mopar1973Man Posted October 3, 2013 Author Administrator Share Posted October 3, 2013 In a nut shell the more weight you shave off of rotational part the more HP/TQ you can put to the ground and the better your MPG's will be. Link to comment Share on other sites More sharing options...
Administrator Mopar1973Man Posted October 3, 2013 Author Administrator Share Posted October 3, 2013 Part 1 Part 2 Link to comment Share on other sites More sharing options...
dorkweed Posted October 3, 2013 Share Posted October 3, 2013 In a nut shell the more weight you shave off of rotational part the more HP/TQ you can put to the ground and the better your MPG's will be. That I understand.................it was looking at all those equations!!!! Link to comment Share on other sites More sharing options...
dripley Posted October 3, 2013 Share Posted October 3, 2013 I am like Ho, I understand the theory but the equations and formulas make my brain throb. Link to comment Share on other sites More sharing options...
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