Hi all, pardon me for what may turn out to be a stupid question.
1999 Dodge 2500 Cummins with an embarrassing amount of money dumped into it.
I used to have an Edge Juice tuner but had to switch to Quadzilla so I could change timing. Edge won't change timing. The Edge tuner does, however, connect to the ODB2 port so you can set read and reset engine codes. Very Handy. Quadzilla does not. I bought a $100 bluetooth ODB2 scanner and hooked that up. I get RPM, temperature, TPS etc from it but NEVER any engine codes.
About a month ago my PCM and transmission fulfilled a long planned suicide pact and that set me back a serious amount of money. Check engine light was never lit. Mechanic pulled the codes for me in the shop (check engine light wasn't lit for him either).
I called tech support for my bluetooth scanner and they say the scanner won't report anything, ever, unless the check engine light is lit. But my Edge tuner DID. Many, many times.
What am I missing here? I sure don't want to shell out that kind of $ again.
Hi all, pardon me for what may turn out to be a stupid question.
1999 Dodge 2500 Cummins with an embarrassing amount of money dumped into it.
I used to have an Edge Juice tuner but had to switch to Quadzilla so I could change timing. Edge won't change timing. The Edge tuner does, however, connect to the ODB2 port so you can set read and reset engine codes. Very Handy. Quadzilla does not. I bought a $100 bluetooth ODB2 scanner and hooked that up. I get RPM, temperature, TPS etc from it but NEVER any engine codes.
About a month ago my PCM and transmission fulfilled a long planned suicide pact and that set me back a serious amount of money. Check engine light was never lit. Mechanic pulled the codes for me in the shop (check engine light wasn't lit for him either).
I called tech support for my bluetooth scanner and they say the scanner won't report anything, ever, unless the check engine light is lit. But my Edge tuner DID. Many, many times.
What am I missing here? I sure don't want to shell out that kind of $ again.
Thanks in advance for your wisdom.